Let A, B, and C be three numbers in continued proportion, and let A the first be square.
I say that C the third is also square.
Since between A and C there is one mean proportional number, B, therefore A and C are similar plane numbers. But A is square, therefore C is also square.
Therefore, if three numbers are in continued proportion, and the first is square, then the third is also square.
This proposition is used in a few propositions in this and the next book starting with VIII.24.
| Book VIII | VIII.24 |
|---|---|
| Book IX | IX.1, IX.8, IX.9 |