Let A, B, C, and D be four magnitudes in proportion, so that A is to B as C is to D, and let A be commensurable with B.
I say that C is also commensurable with D.
Since A is commensurable with B, therefore A has to B the ratio which a number has to a number.
And A is to B as C is to D, therefore C also has to D the ratio which a number has to a number. Therefore C is commensurable with D.
Next, let A be incommensurable with B.
I say that C is also incommensurable with D.
Since A is incommensurable with B, therefore A does not have to B the ratio which a number has to a number.
And A is to B as C is to D, therefore neither has C to D the ratio which a number has to a number. Therefore C is incommensurable with D.
Therefore, if four magnitudes are proportional, and the first is commensurable with the second, then the third also is commensurable with the fourth; but, if the first is incommensurable with the second, then the third also is incommensurable with the fourth.
The proof if very direct. If A : B = C : D, and the first ratio equals a numeric ratio, then the second equals that, too, but if the first is not a numeric ratio, then neither is the second.
This proposition is used in repeatedly in Book X starting with X.14. It is also used in the previous proposition which was, no doubt, not in the original Elements.
| Book X | X.10, X.14, X.19, X.20, X.21, X.22, X.23, X.24, X.25, X.26, X.27, X.28, X.31, X.32, X.34, X.35, X.36, X.38, X.41, X.44, X.47, X.54, X.55, X.57, X.58, X.59, X.60, X.61, X.62, X.63, X.65, X.66, X.67, X.68, X.71, X.72, X.73, X.75, X.78, X.81, X.84, X.91, X.92, X.93, X.94, X.96, X.97, X.98, X.99, X.100, X.101, X.102, X.103, X.104, X.105, X.110, X.112, X.113, X.114 |
|---|